Dim a As RegExp
Set a = New RegExp

a.Global = True
a.Pattern = "\\\\"
s = "abc\\\\|def|gh\\\\\\\\\\\|ij\\kl\\\\\m"
b = a.Replace(s, Chr(7))


a.Pattern = "([^\\])\|"
b = a.Replace(b, "$1 ")
a.Pattern = "\\\|"
b = a.Replace(b, "|")

a.Pattern = "\\(\w)"
b = a.Replace(b, "$1")

a.Pattern = Chr(7)
b = a.Replace(b, "\")

本文发表在 rolia.net 枫下论坛package com.bgi.util;

import java.util.*;


public class Spliter {

public Spliter() {
}
private static String nameOfThisClass = "Spliter";
public final static String DELIMITER = "|";

public static String[] split(String s){
return split(s,DELIMITER);
}

public static String[] split(String s, String delimiter){
checkSource(s);
int delimiterLength;int stringLength = s.length();
if (delimiter == null || (delimiterLength = delimiter.length()) == 0){.
return new String[] {s};
}
int count;
int start;
int end;
char slash = '\\';

// Scan s and count the tokens.
count = 0;
start = 0;
while((end = s.indexOf(delimiter, start)) != -1) {

if (s.charAt(end-1)!=slash){
count++;
start = end + delimiterLength;
} else {
start = end + delimiterLength;
continue;
}}

count++;

String[] result = new String[count];
count = 0;
start = 0;
while((end = s.indexOf(delimiter, start)) != -1) {

if(s.charAt(end-1)!=slash){
result[count] = (s.substring(start, end));
count++;
start = end + delimiterLength;
} else {
start = end + delimiterLength;
continue;
}}

end = stringLength;
result[count] = s.substring(start, end);

return (result);
}

/**
* Check if the input parameter is null
*
* @throws IllegalArgumentException if source is null
*/
private static void checkSource(String source)
throws IllegalArgumentException
{
if ( source == null ){
System.out.println( nameOfThisClass + "The input string is null..");
throw new IllegalArgumentException();
}
}

/**
* Test method
*/
public static void main(String args[]){

try{
String a[]=Spliter.split(args[0]);
int i;
for (i=0; i<a.length; i++ ){
System.out.print(a[i]+"^");
}
}
catch(Exception e){
e.printStackTrace();
}
}

}更多精彩文章及讨论，请光临枫下论坛 rolia.net

I can do it by using StringTokenizer class.

Let me give you an hint: When you get the token, check the "\" char, if you found one replace it with a "|" char and oncatenate it with next token.

本文发表在 rolia.net 枫下论坛import java.util.*;

public class TestTokenization {
private static List tokenize(String str, String dms) {
ArrayList list = new ArrayList( );
StringTokenizer tok = new StringTokenizer(str, dms);
while (tok.hasMoreTokens()) {
list.add(tok.nextToken());
}
return list;
}

private static void refresh(List list, int position, String s) {
if (position >= list.size() ) {
return;
}
String temp = (String) list.get(position);
if (temp.endsWith(s)) {
temp = temp.substring(0, temp.indexOf(s))
+ (String) list.get(position + 1);
list.set(position, temp);
list.remove(position + 1);
}
refresh(list, ++position, s);
}

private static void prt(List list) {
Iterator it = list.iterator();
while (it.hasNext()) {
System.out.print(it.next() + " ");
}
}
public static void main(String[] args) {
String s = "abc\\|ef|gh|lmn\\|\\zx|yw";
List list = tokenize(s, "|");
prt(list);
System.out.println("");
refresh(list, 0, "\\");
prt(list);
}
}更多精彩文章及讨论，请光临枫下论坛 rolia.net